Typsetting diagram chases (with TikZ?) Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)How to define the default vertical distance between nodes?Draw edge on arcNumerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to place nodes in an absolute coordinate system in tikzCommutative diagram with curve connecting between nodesTikz with standalone: pinning tikz coordinates to page cmDrawing a Decision Diagram with Tikz and layout manager
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Typsetting diagram chases (with TikZ?)
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)How to define the default vertical distance between nodes?Draw edge on arcNumerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to place nodes in an absolute coordinate system in tikzCommutative diagram with curve connecting between nodesTikz with standalone: pinning tikz coordinates to page cmDrawing a Decision Diagram with Tikz and layout manager
Background. I recently came across a Youtube video with a bunch of really nicely typeset 'diagram chases' that seem to have been made in TeX (perhaps TikZ?):
I'd like to create something similar for a presentation that I'm working on, but I feel a bit lost when it comes to figuring out a systematic/scalable way to this.
Own attempt. For small diagrams, it's possible to do this in a very ad hoc way, by just playing around with coordinates and the bend right
and bend left
attributes in TikZ. A quick example of what this might look like:
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
begindocument
begintikzpicture[scale=1.5, bend left=15, bend right=15]
node (B) at (0,0) $B$;
node (B') at (0,-1) $B'$;
node (C) at (1,0) $C$;
node (C') at (1,-1) $C'$;
draw[->,gray] (B) -- (B');
draw[->,gray,shorten >= -1pt] (B') -- (C');
draw[->,gray,shorten >= -1pt] (B) -- (C);
draw[->,gray] (C) -- (C');
node (b) at (-0.3,0.2) footnotesize $b$;
node (bprime) at (-0.3,-1.2) footnotesize $b'$;
node (cbar) at (0.7,0.2) footnotesize $barc$;
node (cdiff) at (0.7,-1.3) footnotesize $c'-c''$;
path (b) edge [->[scale=0.7],bend left] node [left] (cbar);
path (b) edge [->[scale=0.7],bend right] node [left] (bprime);
path (bprime) edge [->[scale=0.7],bend right] node [left] (cdiff);
path (cbar) edge [->[scale=0.7],bend right, shorten >= -2pt, shorten <= -1pt] node [left] (cdiff);
endtikzpicture
enddocument
I think this gives a decent end result. But for larger diagrams, it would be an absolute nightmare to work with a code that is so messy and so heavily dependent on coordinates and tweaked parameters.
Thus, if anyone has suggestions (big or small) for a more clever way to do this (with or without TikZ) and/or a way to make my own approach a bit cleaner or more systematic somehow, that would be greatly appreciated!
tikz-pgf diagrams tikz-cd commutative-diagrams
add a comment |
Background. I recently came across a Youtube video with a bunch of really nicely typeset 'diagram chases' that seem to have been made in TeX (perhaps TikZ?):
I'd like to create something similar for a presentation that I'm working on, but I feel a bit lost when it comes to figuring out a systematic/scalable way to this.
Own attempt. For small diagrams, it's possible to do this in a very ad hoc way, by just playing around with coordinates and the bend right
and bend left
attributes in TikZ. A quick example of what this might look like:
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
begindocument
begintikzpicture[scale=1.5, bend left=15, bend right=15]
node (B) at (0,0) $B$;
node (B') at (0,-1) $B'$;
node (C) at (1,0) $C$;
node (C') at (1,-1) $C'$;
draw[->,gray] (B) -- (B');
draw[->,gray,shorten >= -1pt] (B') -- (C');
draw[->,gray,shorten >= -1pt] (B) -- (C);
draw[->,gray] (C) -- (C');
node (b) at (-0.3,0.2) footnotesize $b$;
node (bprime) at (-0.3,-1.2) footnotesize $b'$;
node (cbar) at (0.7,0.2) footnotesize $barc$;
node (cdiff) at (0.7,-1.3) footnotesize $c'-c''$;
path (b) edge [->[scale=0.7],bend left] node [left] (cbar);
path (b) edge [->[scale=0.7],bend right] node [left] (bprime);
path (bprime) edge [->[scale=0.7],bend right] node [left] (cdiff);
path (cbar) edge [->[scale=0.7],bend right, shorten >= -2pt, shorten <= -1pt] node [left] (cdiff);
endtikzpicture
enddocument
I think this gives a decent end result. But for larger diagrams, it would be an absolute nightmare to work with a code that is so messy and so heavily dependent on coordinates and tweaked parameters.
Thus, if anyone has suggestions (big or small) for a more clever way to do this (with or without TikZ) and/or a way to make my own approach a bit cleaner or more systematic somehow, that would be greatly appreciated!
tikz-pgf diagrams tikz-cd commutative-diagrams
The diagram was created with a very nice tool, but that is not TikZ (as far as I can see). Anyway, it is always possible to create the diagram using TikZ.
– JouleV
2 hours ago
Any other tools that you think could be useful? I'm definitely willing to try out other tools than TikZ if need be!
– Oskar Henriksson
1 hour ago
add a comment |
Background. I recently came across a Youtube video with a bunch of really nicely typeset 'diagram chases' that seem to have been made in TeX (perhaps TikZ?):
I'd like to create something similar for a presentation that I'm working on, but I feel a bit lost when it comes to figuring out a systematic/scalable way to this.
Own attempt. For small diagrams, it's possible to do this in a very ad hoc way, by just playing around with coordinates and the bend right
and bend left
attributes in TikZ. A quick example of what this might look like:
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
begindocument
begintikzpicture[scale=1.5, bend left=15, bend right=15]
node (B) at (0,0) $B$;
node (B') at (0,-1) $B'$;
node (C) at (1,0) $C$;
node (C') at (1,-1) $C'$;
draw[->,gray] (B) -- (B');
draw[->,gray,shorten >= -1pt] (B') -- (C');
draw[->,gray,shorten >= -1pt] (B) -- (C);
draw[->,gray] (C) -- (C');
node (b) at (-0.3,0.2) footnotesize $b$;
node (bprime) at (-0.3,-1.2) footnotesize $b'$;
node (cbar) at (0.7,0.2) footnotesize $barc$;
node (cdiff) at (0.7,-1.3) footnotesize $c'-c''$;
path (b) edge [->[scale=0.7],bend left] node [left] (cbar);
path (b) edge [->[scale=0.7],bend right] node [left] (bprime);
path (bprime) edge [->[scale=0.7],bend right] node [left] (cdiff);
path (cbar) edge [->[scale=0.7],bend right, shorten >= -2pt, shorten <= -1pt] node [left] (cdiff);
endtikzpicture
enddocument
I think this gives a decent end result. But for larger diagrams, it would be an absolute nightmare to work with a code that is so messy and so heavily dependent on coordinates and tweaked parameters.
Thus, if anyone has suggestions (big or small) for a more clever way to do this (with or without TikZ) and/or a way to make my own approach a bit cleaner or more systematic somehow, that would be greatly appreciated!
tikz-pgf diagrams tikz-cd commutative-diagrams
Background. I recently came across a Youtube video with a bunch of really nicely typeset 'diagram chases' that seem to have been made in TeX (perhaps TikZ?):
I'd like to create something similar for a presentation that I'm working on, but I feel a bit lost when it comes to figuring out a systematic/scalable way to this.
Own attempt. For small diagrams, it's possible to do this in a very ad hoc way, by just playing around with coordinates and the bend right
and bend left
attributes in TikZ. A quick example of what this might look like:
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
begindocument
begintikzpicture[scale=1.5, bend left=15, bend right=15]
node (B) at (0,0) $B$;
node (B') at (0,-1) $B'$;
node (C) at (1,0) $C$;
node (C') at (1,-1) $C'$;
draw[->,gray] (B) -- (B');
draw[->,gray,shorten >= -1pt] (B') -- (C');
draw[->,gray,shorten >= -1pt] (B) -- (C);
draw[->,gray] (C) -- (C');
node (b) at (-0.3,0.2) footnotesize $b$;
node (bprime) at (-0.3,-1.2) footnotesize $b'$;
node (cbar) at (0.7,0.2) footnotesize $barc$;
node (cdiff) at (0.7,-1.3) footnotesize $c'-c''$;
path (b) edge [->[scale=0.7],bend left] node [left] (cbar);
path (b) edge [->[scale=0.7],bend right] node [left] (bprime);
path (bprime) edge [->[scale=0.7],bend right] node [left] (cdiff);
path (cbar) edge [->[scale=0.7],bend right, shorten >= -2pt, shorten <= -1pt] node [left] (cdiff);
endtikzpicture
enddocument
I think this gives a decent end result. But for larger diagrams, it would be an absolute nightmare to work with a code that is so messy and so heavily dependent on coordinates and tweaked parameters.
Thus, if anyone has suggestions (big or small) for a more clever way to do this (with or without TikZ) and/or a way to make my own approach a bit cleaner or more systematic somehow, that would be greatly appreciated!
tikz-pgf diagrams tikz-cd commutative-diagrams
tikz-pgf diagrams tikz-cd commutative-diagrams
edited 31 mins ago
JouleV
13.5k22664
13.5k22664
asked 2 hours ago
Oskar HenrikssonOskar Henriksson
1256
1256
The diagram was created with a very nice tool, but that is not TikZ (as far as I can see). Anyway, it is always possible to create the diagram using TikZ.
– JouleV
2 hours ago
Any other tools that you think could be useful? I'm definitely willing to try out other tools than TikZ if need be!
– Oskar Henriksson
1 hour ago
add a comment |
The diagram was created with a very nice tool, but that is not TikZ (as far as I can see). Anyway, it is always possible to create the diagram using TikZ.
– JouleV
2 hours ago
Any other tools that you think could be useful? I'm definitely willing to try out other tools than TikZ if need be!
– Oskar Henriksson
1 hour ago
The diagram was created with a very nice tool, but that is not TikZ (as far as I can see). Anyway, it is always possible to create the diagram using TikZ.
– JouleV
2 hours ago
The diagram was created with a very nice tool, but that is not TikZ (as far as I can see). Anyway, it is always possible to create the diagram using TikZ.
– JouleV
2 hours ago
Any other tools that you think could be useful? I'm definitely willing to try out other tools than TikZ if need be!
– Oskar Henriksson
1 hour ago
Any other tools that you think could be useful? I'm definitely willing to try out other tools than TikZ if need be!
– Oskar Henriksson
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
We clearly can't avoid difficulties and complexity when dealing with such a complicated graph when using any kinds of tool, but by using matrices it has saved a lot of work.
documentclass[tikz]standalone
usetikzlibrarymatrix,positioning,arrows.meta
usepackagemathptmx
tikzsettoarrow/.style=->[scale=0.7],
backarrow/.style=<[scale=0.7]-
begindocument
begintikzpicture
matrix[matrix of math nodes,row sep=2cm,column sep=2cm] (m) %
A & B & C & D & E\
A' & B' & C' & D' & E'\;
path (m-1-2) node[above left=1.5ex and 1.5ex] (b) $b$
(m-1-3) node[above left=1.5ex and 1.5ex] (c) $c$
(m-1-4) node[above left=1.5ex and 1.5ex] (d) $d$
(m-1-5) node[above left=1.5ex and 1.5ex] (e) $e$
(m-2-2) node[below left=1.5ex and 1.5ex] (b2) $b'$
(m-2-3) node[below left=1.5ex and 1.5ex] (c2) $c'$
(m-2-4) node[below left=1.5ex and 1.5ex] (d2) $d'$
(m-2-5) node[below left=1.5ex and 1.5ex] (e2) $0$
(m-2-3) node[above left=1.5ex and 1.5ex] (c3) $c''$
(c) node[above left=1.5ex and -1.5ex] (cp) $overlinec+c$
(c2) node[below=1.5ex] (cm) $c'-c''$
(d2) node[below=1.5ex] (db) $0$
(e.base east) node[above right=-.3333em and -1ex] $=0$
(c.base west) node[above left=-.3333em and 1.5ex] (co) $overlinec$;
% Delete the following part to see what happens
foreach i [count=j from 2] in 1,2,3,4
draw[dotted,->] (m-1-i) -- (m-2-i);
draw[dotted,->] (m-1-i) -- (m-1-j);
draw[dotted,->] (m-2-i) -- (m-2-j);
draw[dotted,->] (m-1-5) -- (m-2-5);
draw[toarrow] (b) edge[bend right] (b2) edge[bend left] (co);
draw[toarrow] (b2) to[bend right] (cm);
draw[toarrow] (cm) to[bend right] (db);
draw[toarrow] (co) to[bend right] (cm);
draw[toarrow] (cp) to[bend right] (c2);
draw[toarrow] (c) edge[bend right] (c3) edge[bend left] (d);
draw[backarrow] (d2) edge[bend left] (c2) edge[bend right=20] (c3) edge[bend left] (d);
draw[backarrow] (e2) edge[bend left] (d2) edge[bend left] (e);
draw[toarrow] (d) edge[bend left] (e);
endtikzpicture
enddocument
add a comment |
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1 Answer
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votes
We clearly can't avoid difficulties and complexity when dealing with such a complicated graph when using any kinds of tool, but by using matrices it has saved a lot of work.
documentclass[tikz]standalone
usetikzlibrarymatrix,positioning,arrows.meta
usepackagemathptmx
tikzsettoarrow/.style=->[scale=0.7],
backarrow/.style=<[scale=0.7]-
begindocument
begintikzpicture
matrix[matrix of math nodes,row sep=2cm,column sep=2cm] (m) %
A & B & C & D & E\
A' & B' & C' & D' & E'\;
path (m-1-2) node[above left=1.5ex and 1.5ex] (b) $b$
(m-1-3) node[above left=1.5ex and 1.5ex] (c) $c$
(m-1-4) node[above left=1.5ex and 1.5ex] (d) $d$
(m-1-5) node[above left=1.5ex and 1.5ex] (e) $e$
(m-2-2) node[below left=1.5ex and 1.5ex] (b2) $b'$
(m-2-3) node[below left=1.5ex and 1.5ex] (c2) $c'$
(m-2-4) node[below left=1.5ex and 1.5ex] (d2) $d'$
(m-2-5) node[below left=1.5ex and 1.5ex] (e2) $0$
(m-2-3) node[above left=1.5ex and 1.5ex] (c3) $c''$
(c) node[above left=1.5ex and -1.5ex] (cp) $overlinec+c$
(c2) node[below=1.5ex] (cm) $c'-c''$
(d2) node[below=1.5ex] (db) $0$
(e.base east) node[above right=-.3333em and -1ex] $=0$
(c.base west) node[above left=-.3333em and 1.5ex] (co) $overlinec$;
% Delete the following part to see what happens
foreach i [count=j from 2] in 1,2,3,4
draw[dotted,->] (m-1-i) -- (m-2-i);
draw[dotted,->] (m-1-i) -- (m-1-j);
draw[dotted,->] (m-2-i) -- (m-2-j);
draw[dotted,->] (m-1-5) -- (m-2-5);
draw[toarrow] (b) edge[bend right] (b2) edge[bend left] (co);
draw[toarrow] (b2) to[bend right] (cm);
draw[toarrow] (cm) to[bend right] (db);
draw[toarrow] (co) to[bend right] (cm);
draw[toarrow] (cp) to[bend right] (c2);
draw[toarrow] (c) edge[bend right] (c3) edge[bend left] (d);
draw[backarrow] (d2) edge[bend left] (c2) edge[bend right=20] (c3) edge[bend left] (d);
draw[backarrow] (e2) edge[bend left] (d2) edge[bend left] (e);
draw[toarrow] (d) edge[bend left] (e);
endtikzpicture
enddocument
add a comment |
We clearly can't avoid difficulties and complexity when dealing with such a complicated graph when using any kinds of tool, but by using matrices it has saved a lot of work.
documentclass[tikz]standalone
usetikzlibrarymatrix,positioning,arrows.meta
usepackagemathptmx
tikzsettoarrow/.style=->[scale=0.7],
backarrow/.style=<[scale=0.7]-
begindocument
begintikzpicture
matrix[matrix of math nodes,row sep=2cm,column sep=2cm] (m) %
A & B & C & D & E\
A' & B' & C' & D' & E'\;
path (m-1-2) node[above left=1.5ex and 1.5ex] (b) $b$
(m-1-3) node[above left=1.5ex and 1.5ex] (c) $c$
(m-1-4) node[above left=1.5ex and 1.5ex] (d) $d$
(m-1-5) node[above left=1.5ex and 1.5ex] (e) $e$
(m-2-2) node[below left=1.5ex and 1.5ex] (b2) $b'$
(m-2-3) node[below left=1.5ex and 1.5ex] (c2) $c'$
(m-2-4) node[below left=1.5ex and 1.5ex] (d2) $d'$
(m-2-5) node[below left=1.5ex and 1.5ex] (e2) $0$
(m-2-3) node[above left=1.5ex and 1.5ex] (c3) $c''$
(c) node[above left=1.5ex and -1.5ex] (cp) $overlinec+c$
(c2) node[below=1.5ex] (cm) $c'-c''$
(d2) node[below=1.5ex] (db) $0$
(e.base east) node[above right=-.3333em and -1ex] $=0$
(c.base west) node[above left=-.3333em and 1.5ex] (co) $overlinec$;
% Delete the following part to see what happens
foreach i [count=j from 2] in 1,2,3,4
draw[dotted,->] (m-1-i) -- (m-2-i);
draw[dotted,->] (m-1-i) -- (m-1-j);
draw[dotted,->] (m-2-i) -- (m-2-j);
draw[dotted,->] (m-1-5) -- (m-2-5);
draw[toarrow] (b) edge[bend right] (b2) edge[bend left] (co);
draw[toarrow] (b2) to[bend right] (cm);
draw[toarrow] (cm) to[bend right] (db);
draw[toarrow] (co) to[bend right] (cm);
draw[toarrow] (cp) to[bend right] (c2);
draw[toarrow] (c) edge[bend right] (c3) edge[bend left] (d);
draw[backarrow] (d2) edge[bend left] (c2) edge[bend right=20] (c3) edge[bend left] (d);
draw[backarrow] (e2) edge[bend left] (d2) edge[bend left] (e);
draw[toarrow] (d) edge[bend left] (e);
endtikzpicture
enddocument
add a comment |
We clearly can't avoid difficulties and complexity when dealing with such a complicated graph when using any kinds of tool, but by using matrices it has saved a lot of work.
documentclass[tikz]standalone
usetikzlibrarymatrix,positioning,arrows.meta
usepackagemathptmx
tikzsettoarrow/.style=->[scale=0.7],
backarrow/.style=<[scale=0.7]-
begindocument
begintikzpicture
matrix[matrix of math nodes,row sep=2cm,column sep=2cm] (m) %
A & B & C & D & E\
A' & B' & C' & D' & E'\;
path (m-1-2) node[above left=1.5ex and 1.5ex] (b) $b$
(m-1-3) node[above left=1.5ex and 1.5ex] (c) $c$
(m-1-4) node[above left=1.5ex and 1.5ex] (d) $d$
(m-1-5) node[above left=1.5ex and 1.5ex] (e) $e$
(m-2-2) node[below left=1.5ex and 1.5ex] (b2) $b'$
(m-2-3) node[below left=1.5ex and 1.5ex] (c2) $c'$
(m-2-4) node[below left=1.5ex and 1.5ex] (d2) $d'$
(m-2-5) node[below left=1.5ex and 1.5ex] (e2) $0$
(m-2-3) node[above left=1.5ex and 1.5ex] (c3) $c''$
(c) node[above left=1.5ex and -1.5ex] (cp) $overlinec+c$
(c2) node[below=1.5ex] (cm) $c'-c''$
(d2) node[below=1.5ex] (db) $0$
(e.base east) node[above right=-.3333em and -1ex] $=0$
(c.base west) node[above left=-.3333em and 1.5ex] (co) $overlinec$;
% Delete the following part to see what happens
foreach i [count=j from 2] in 1,2,3,4
draw[dotted,->] (m-1-i) -- (m-2-i);
draw[dotted,->] (m-1-i) -- (m-1-j);
draw[dotted,->] (m-2-i) -- (m-2-j);
draw[dotted,->] (m-1-5) -- (m-2-5);
draw[toarrow] (b) edge[bend right] (b2) edge[bend left] (co);
draw[toarrow] (b2) to[bend right] (cm);
draw[toarrow] (cm) to[bend right] (db);
draw[toarrow] (co) to[bend right] (cm);
draw[toarrow] (cp) to[bend right] (c2);
draw[toarrow] (c) edge[bend right] (c3) edge[bend left] (d);
draw[backarrow] (d2) edge[bend left] (c2) edge[bend right=20] (c3) edge[bend left] (d);
draw[backarrow] (e2) edge[bend left] (d2) edge[bend left] (e);
draw[toarrow] (d) edge[bend left] (e);
endtikzpicture
enddocument
We clearly can't avoid difficulties and complexity when dealing with such a complicated graph when using any kinds of tool, but by using matrices it has saved a lot of work.
documentclass[tikz]standalone
usetikzlibrarymatrix,positioning,arrows.meta
usepackagemathptmx
tikzsettoarrow/.style=->[scale=0.7],
backarrow/.style=<[scale=0.7]-
begindocument
begintikzpicture
matrix[matrix of math nodes,row sep=2cm,column sep=2cm] (m) %
A & B & C & D & E\
A' & B' & C' & D' & E'\;
path (m-1-2) node[above left=1.5ex and 1.5ex] (b) $b$
(m-1-3) node[above left=1.5ex and 1.5ex] (c) $c$
(m-1-4) node[above left=1.5ex and 1.5ex] (d) $d$
(m-1-5) node[above left=1.5ex and 1.5ex] (e) $e$
(m-2-2) node[below left=1.5ex and 1.5ex] (b2) $b'$
(m-2-3) node[below left=1.5ex and 1.5ex] (c2) $c'$
(m-2-4) node[below left=1.5ex and 1.5ex] (d2) $d'$
(m-2-5) node[below left=1.5ex and 1.5ex] (e2) $0$
(m-2-3) node[above left=1.5ex and 1.5ex] (c3) $c''$
(c) node[above left=1.5ex and -1.5ex] (cp) $overlinec+c$
(c2) node[below=1.5ex] (cm) $c'-c''$
(d2) node[below=1.5ex] (db) $0$
(e.base east) node[above right=-.3333em and -1ex] $=0$
(c.base west) node[above left=-.3333em and 1.5ex] (co) $overlinec$;
% Delete the following part to see what happens
foreach i [count=j from 2] in 1,2,3,4
draw[dotted,->] (m-1-i) -- (m-2-i);
draw[dotted,->] (m-1-i) -- (m-1-j);
draw[dotted,->] (m-2-i) -- (m-2-j);
draw[dotted,->] (m-1-5) -- (m-2-5);
draw[toarrow] (b) edge[bend right] (b2) edge[bend left] (co);
draw[toarrow] (b2) to[bend right] (cm);
draw[toarrow] (cm) to[bend right] (db);
draw[toarrow] (co) to[bend right] (cm);
draw[toarrow] (cp) to[bend right] (c2);
draw[toarrow] (c) edge[bend right] (c3) edge[bend left] (d);
draw[backarrow] (d2) edge[bend left] (c2) edge[bend right=20] (c3) edge[bend left] (d);
draw[backarrow] (e2) edge[bend left] (d2) edge[bend left] (e);
draw[toarrow] (d) edge[bend left] (e);
endtikzpicture
enddocument
edited 1 hour ago
answered 1 hour ago
JouleVJouleV
13.5k22664
13.5k22664
add a comment |
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The diagram was created with a very nice tool, but that is not TikZ (as far as I can see). Anyway, it is always possible to create the diagram using TikZ.
– JouleV
2 hours ago
Any other tools that you think could be useful? I'm definitely willing to try out other tools than TikZ if need be!
– Oskar Henriksson
1 hour ago