How to format long polynomial?Why are default LaTeX margins so big?Polynomial Long Division over GF(p)Why does widehat behave differently if I insert hspace0pt?Converting all numbers in document to set number of decimal placesShortcuts and/or user-defined shortcuts for math symbols in LaTeX?How to construct a long equation that is split in LHS and RHS to occupy a narrow column?Using mathspec to change digits font in math mode isn't workingCorrect typesetting of a formula with a long fractionWriting Lines and Lines of Math Without Continuation CharactersHow continue a equation next lineIn the figure form, adjust the whole size of “text” and “math” format at once (II): from twocolumngrid to onecolumngrid
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How to format long polynomial?
Why are default LaTeX margins so big?Polynomial Long Division over GF(p)Why does widehat behave differently if I insert hspace0pt?Converting all numbers in document to set number of decimal placesShortcuts and/or user-defined shortcuts for math symbols in LaTeX?How to construct a long equation that is split in LHS and RHS to occupy a narrow column?Using mathspec to change digits font in math mode isn't workingCorrect typesetting of a formula with a long fractionWriting Lines and Lines of Math Without Continuation CharactersHow continue a equation next lineIn the figure form, adjust the whole size of “text” and “math” format at once (II): from twocolumngrid to onecolumngrid
I have a long polynomial:
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument
Question. How to format such long polynomial correctly?
math-mode
add a comment |
I have a long polynomial:
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument
Question. How to format such long polynomial correctly?
math-mode
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.
– Mefitico
16 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
15 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
15 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
15 hours ago
add a comment |
I have a long polynomial:
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument
Question. How to format such long polynomial correctly?
math-mode
I have a long polynomial:
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument
Question. How to format such long polynomial correctly?
math-mode
math-mode
edited 20 hours ago
Bernard
175k777207
175k777207
asked 20 hours ago
NickNick
1915
1915
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.
– Mefitico
16 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
15 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
15 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
15 hours ago
add a comment |
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.
– Mefitico
16 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
15 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
15 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
15 hours ago
3
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.
– Mefitico
16 hours ago
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.
– Mefitico
16 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
15 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
15 hours ago
1
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
15 hours ago
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
15 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
15 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
15 hours ago
add a comment |
7 Answers
7
active
oldest
votes
I suggest something line the following, so the wide terms are reduced.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
begingather*
beginalign*
g(eta,z)&=
parbox[t]0.85displaywidthraggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endalign*
\[2ex]
f(z)=frac1382112640fracg(eta,z)h(z)
endgather*
enddocument
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
add a comment |
I would use something like this
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
beginalign*
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
endalign*
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
enddocument
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
12 hours ago
add a comment |
or
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools, nccmath
begindocument
beginmultline*medmath
f(z)=frac1382112640
fracleft[
beginmultlined
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
endmultlinedright]
(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endmultline*
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac1382112640 fracg(eta, z)u(z) , v(z) , w(z) $$
where
$$
beginarrayll
g(eta, z) = beginbmatrix
beginarrayr @hspace0em l
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
endarray
endbmatrix^T
beginbmatrix
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
endbmatrix &
beginarrayl
u(z) = left ( beginbmatrix 417420 \ -4169121 \ -15571312 endbmatrix^T beginbmatrix z^2 \ z \ 1 endbmatrix right ) \[3em]
v(z) = left ( beginbmatrix 1546 \ 3537 endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
w(z) = left ( beginbmatrix 3092 \ 17001endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
endarray
endarray
$$
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
[
arraycolsep=0.5pt
beginarrayrrllrll
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
endarray
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
enddocument
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclassarticle
usepackagemathtools
begindocument
beginalignat*2
& f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) times frac417420z^2-4169121z-15571312(1546z+3537)(3092z+17001)
endalignat*
Do you think this fits the page margin?
– JouleV
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begindmath*
f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
enddmath*
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
add a comment |
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I suggest something line the following, so the wide terms are reduced.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
begingather*
beginalign*
g(eta,z)&=
parbox[t]0.85displaywidthraggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endalign*
\[2ex]
f(z)=frac1382112640fracg(eta,z)h(z)
endgather*
enddocument
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
add a comment |
I suggest something line the following, so the wide terms are reduced.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
begingather*
beginalign*
g(eta,z)&=
parbox[t]0.85displaywidthraggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endalign*
\[2ex]
f(z)=frac1382112640fracg(eta,z)h(z)
endgather*
enddocument
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
add a comment |
I suggest something line the following, so the wide terms are reduced.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
begingather*
beginalign*
g(eta,z)&=
parbox[t]0.85displaywidthraggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endalign*
\[2ex]
f(z)=frac1382112640fracg(eta,z)h(z)
endgather*
enddocument
I suggest something line the following, so the wide terms are reduced.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
begingather*
beginalign*
g(eta,z)&=
parbox[t]0.85displaywidthraggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endalign*
\[2ex]
f(z)=frac1382112640fracg(eta,z)h(z)
endgather*
enddocument
answered 20 hours ago
egregegreg
732k8919303253
732k8919303253
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
add a comment |
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
your answer is OK, but some terms are out of pages margins.
– Nick
20 hours ago
5
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
19 hours ago
@Nick egreg's answer uses default margin of
article
, which is already really big. But it doesn't fit your margin?– JouleV
19 hours ago
@Nick egreg's answer uses default margin of
article
, which is already really big. But it doesn't fit your margin?– JouleV
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
19 hours ago
add a comment |
I would use something like this
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
beginalign*
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
endalign*
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
enddocument
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
12 hours ago
add a comment |
I would use something like this
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
beginalign*
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
endalign*
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
enddocument
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
12 hours ago
add a comment |
I would use something like this
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
beginalign*
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
endalign*
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
enddocument
I would use something like this
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
beginalign*
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
endalign*
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
enddocument
answered 20 hours ago
JouleVJouleV
10.9k22560
10.9k22560
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
12 hours ago
add a comment |
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
12 hours ago
you could format this even more compactly by using matrix multiplication to express
A
– Tasos Papastylianou
12 hours ago
you could format this even more compactly by using matrix multiplication to express
A
– Tasos Papastylianou
12 hours ago
add a comment |
or
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools, nccmath
begindocument
beginmultline*medmath
f(z)=frac1382112640
fracleft[
beginmultlined
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
endmultlinedright]
(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endmultline*
add a comment |
or
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools, nccmath
begindocument
beginmultline*medmath
f(z)=frac1382112640
fracleft[
beginmultlined
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
endmultlinedright]
(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endmultline*
add a comment |
or
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools, nccmath
begindocument
beginmultline*medmath
f(z)=frac1382112640
fracleft[
beginmultlined
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
endmultlinedright]
(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endmultline*
or
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools, nccmath
begindocument
beginmultline*medmath
f(z)=frac1382112640
fracleft[
beginmultlined
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
endmultlinedright]
(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endmultline*
answered 20 hours ago
ZarkoZarko
129k868169
129k868169
add a comment |
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac1382112640 fracg(eta, z)u(z) , v(z) , w(z) $$
where
$$
beginarrayll
g(eta, z) = beginbmatrix
beginarrayr @hspace0em l
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
endarray
endbmatrix^T
beginbmatrix
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
endbmatrix &
beginarrayl
u(z) = left ( beginbmatrix 417420 \ -4169121 \ -15571312 endbmatrix^T beginbmatrix z^2 \ z \ 1 endbmatrix right ) \[3em]
v(z) = left ( beginbmatrix 1546 \ 3537 endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
w(z) = left ( beginbmatrix 3092 \ 17001endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
endarray
endarray
$$
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac1382112640 fracg(eta, z)u(z) , v(z) , w(z) $$
where
$$
beginarrayll
g(eta, z) = beginbmatrix
beginarrayr @hspace0em l
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
endarray
endbmatrix^T
beginbmatrix
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
endbmatrix &
beginarrayl
u(z) = left ( beginbmatrix 417420 \ -4169121 \ -15571312 endbmatrix^T beginbmatrix z^2 \ z \ 1 endbmatrix right ) \[3em]
v(z) = left ( beginbmatrix 1546 \ 3537 endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
w(z) = left ( beginbmatrix 3092 \ 17001endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
endarray
endarray
$$
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac1382112640 fracg(eta, z)u(z) , v(z) , w(z) $$
where
$$
beginarrayll
g(eta, z) = beginbmatrix
beginarrayr @hspace0em l
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
endarray
endbmatrix^T
beginbmatrix
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
endbmatrix &
beginarrayl
u(z) = left ( beginbmatrix 417420 \ -4169121 \ -15571312 endbmatrix^T beginbmatrix z^2 \ z \ 1 endbmatrix right ) \[3em]
v(z) = left ( beginbmatrix 1546 \ 3537 endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
w(z) = left ( beginbmatrix 3092 \ 17001endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
endarray
endarray
$$
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac1382112640 fracg(eta, z)u(z) , v(z) , w(z) $$
where
$$
beginarrayll
g(eta, z) = beginbmatrix
beginarrayr @hspace0em l
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
endarray
endbmatrix^T
beginbmatrix
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
endbmatrix &
beginarrayl
u(z) = left ( beginbmatrix 417420 \ -4169121 \ -15571312 endbmatrix^T beginbmatrix z^2 \ z \ 1 endbmatrix right ) \[3em]
v(z) = left ( beginbmatrix 1546 \ 3537 endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
w(z) = left ( beginbmatrix 3092 \ 17001endbmatrix^T beginbmatrix z \ 1 endbmatrix right ) \[3em]
endarray
endarray
$$
edited 11 hours ago
answered 11 hours ago
Tasos PapastylianouTasos Papastylianou
297211
297211
add a comment |
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
[
arraycolsep=0.5pt
beginarrayrrllrll
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
endarray
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
enddocument
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
[
arraycolsep=0.5pt
beginarrayrrllrll
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
endarray
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
enddocument
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
[
arraycolsep=0.5pt
beginarrayrrllrll
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
endarray
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
enddocument
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
[
arraycolsep=0.5pt
beginarrayrrllrll
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
endarray
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
enddocument
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
answered 17 hours ago
flawrflawr
517413
517413
add a comment |
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclassarticle
usepackagemathtools
begindocument
beginalignat*2
& f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) times frac417420z^2-4169121z-15571312(1546z+3537)(3092z+17001)
endalignat*
Do you think this fits the page margin?
– JouleV
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclassarticle
usepackagemathtools
begindocument
beginalignat*2
& f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) times frac417420z^2-4169121z-15571312(1546z+3537)(3092z+17001)
endalignat*
Do you think this fits the page margin?
– JouleV
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclassarticle
usepackagemathtools
begindocument
beginalignat*2
& f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) times frac417420z^2-4169121z-15571312(1546z+3537)(3092z+17001)
endalignat*
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclassarticle
usepackagemathtools
begindocument
beginalignat*2
& f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) times frac417420z^2-4169121z-15571312(1546z+3537)(3092z+17001)
endalignat*
answered 18 hours ago
AndreAndre
1768
1768
Do you think this fits the page margin?
– JouleV
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
add a comment |
Do you think this fits the page margin?
– JouleV
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
Do you think this fits the page margin?
– JouleV
18 hours ago
Do you think this fits the page margin?
– JouleV
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
18 hours ago
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begindmath*
f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
enddmath*
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begindmath*
f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
enddmath*
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begindmath*
f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
enddmath*
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begindmath*
f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
enddmath*
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
answered 14 hours ago
PhilipPhilip
235
235
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3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.
– Mefitico
16 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
15 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
15 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
15 hours ago