Does higher Oxidation/ reduction potential translate to higher energy storage in battery? The Next CEO of Stack OverflowCan we create a galvanic cell with only half a cell connected to the ground?How can Nernst equation apply in this redox reaction?What are some factors that influence the voltage of voltaic/galvanic cells and why?ElectrochemistryWhat factors could lower the voltage of a galvanic cellElectrode Potential and Effect of Salt Bridge Ions on its ValueWhy does a complete discharge destroy a Li-Ion-Battery?Is flow battery cycle life really as high as the literature claims?water in redox reactionsRelationship between Yield and Applied Potentials

Does higher Oxidation/ reduction potential translate to higher energy storage in battery?

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Does higher Oxidation/ reduction potential translate to higher energy storage in battery?



The Next CEO of Stack OverflowCan we create a galvanic cell with only half a cell connected to the ground?How can Nernst equation apply in this redox reaction?What are some factors that influence the voltage of voltaic/galvanic cells and why?ElectrochemistryWhat factors could lower the voltage of a galvanic cellElectrode Potential and Effect of Salt Bridge Ions on its ValueWhy does a complete discharge destroy a Li-Ion-Battery?Is flow battery cycle life really as high as the literature claims?water in redox reactionsRelationship between Yield and Applied Potentials










1












$begingroup$


Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)



If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?










share|improve this question







New contributor




Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$







  • 1




    $begingroup$
    There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
    $endgroup$
    – MaxW
    7 hours ago















1












$begingroup$


Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)



If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?










share|improve this question







New contributor




Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
    $endgroup$
    – MaxW
    7 hours ago













1












1








1





$begingroup$


Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)



If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?










share|improve this question







New contributor




Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)



If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?







electrochemistry






share|improve this question







New contributor




Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 7 hours ago









Karthick SKarthick S

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61




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Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 1




    $begingroup$
    There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
    $endgroup$
    – MaxW
    7 hours ago












  • 1




    $begingroup$
    There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
    $endgroup$
    – MaxW
    7 hours ago







1




1




$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago




$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago










1 Answer
1






active

oldest

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4












$begingroup$

Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.



Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.



So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.






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    1 Answer
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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

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    4












    $begingroup$

    Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.



    Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.



    So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.






    share|improve this answer











    $endgroup$

















      4












      $begingroup$

      Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.



      Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.



      So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.






      share|improve this answer











      $endgroup$















        4












        4








        4





        $begingroup$

        Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.



        Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.



        So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.






        share|improve this answer











        $endgroup$



        Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.



        Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.



        So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 29 mins ago

























        answered 5 hours ago









        DrMoishe PippikDrMoishe Pippik

        14.5k1231




        14.5k1231




















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