Intersection of two sorted vectors in C++A pointer vector sorted by its member functionShould I call a method (i.e. size()) multiple times or store it (if I know the value will not change)Is this implementation of Quicksort good?Computing intersection of 2D infinite linesMerge two already sorted linked listPlace integers into a vector, sum each adjacent pair, refill vector with only the sums of each pair i.e remove all the original data from the vectorMerge two sorted lists of numbersFinding the lowest missing integer in a vector containing negative and positive valuesDemonstration of Scale BalancingType-safe Euclidean vectors in C++

Do I have a twin with permutated remainders?

Emailing HOD to enhance faculty application

Is it unprofessional to ask if a job posting on GlassDoor is real?

What's the difference between 'rename' and 'mv'?

Can a rocket refuel on Mars from water?

What is the most common color to indicate the input-field is disabled?

How do conventional missiles fly?

1960's book about a plague that kills all white people

Watching something be written to a file live with tail

Is it possible to run Internet Explorer on OS X El Capitan?

I'm flying to France today and my passport expires in less than 2 months

If human space travel is limited by the G force vulnerability, is there a way to counter G forces?

Western buddy movie with a supernatural twist where a woman turns into an eagle at the end

What is the intuition behind short exact sequences of groups; in particular, what is the intuition behind group extensions?

How to say in German "enjoying home comforts"

How could indestructible materials be used in power generation?

Is it inappropriate for a student to attend their mentor's dissertation defense?

Can one be a co-translator of a book, if he does not know the language that the book is translated into?

A reference to a well-known characterization of scattered compact spaces

Is it legal for company to use my work email to pretend I still work there?

How to model explosives?

If a Gelatinous Cube takes up the entire space of a Pit Trap, what happens when a creature falls into the trap but succeeds on the saving throw?

What is the word for reserving something for yourself before others do?

How can saying a song's name be a copyright violation?



Intersection of two sorted vectors in C++


A pointer vector sorted by its member functionShould I call a method (i.e. size()) multiple times or store it (if I know the value will not change)Is this implementation of Quicksort good?Computing intersection of 2D infinite linesMerge two already sorted linked listPlace integers into a vector, sum each adjacent pair, refill vector with only the sums of each pair i.e remove all the original data from the vectorMerge two sorted lists of numbersFinding the lowest missing integer in a vector containing negative and positive valuesDemonstration of Scale BalancingType-safe Euclidean vectors in C++






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4












$begingroup$


Intersection of two sorted vectors in C++ - can this be written any better?



vector<int> intersection(vector<int>& nums1, vector<int>& nums2) 
vector<int> result;
int l = 0, r = 0;
while(l < nums1.size() && r < nums2.size())
int left = nums1[l], right = nums2[r];
if(left == right)
result.push_back(right);
while(l < nums1.size() && nums1[l] == left )l++;
while(r < nums2.size() && nums2[r] == right )r++;
continue;

if(left < right)
while(l < nums1.size() && nums1[l] == left )l++;
else while( r < nums2.size() && nums2[r] == right )r++;

return result;










share|improve this question











$endgroup$







  • 4




    $begingroup$
    Do you know about std::set_intersection()? Reference and example implementations: en.cppreference.com/w/cpp/algorithm/set_intersection
    $endgroup$
    – user673679
    12 hours ago






  • 2




    $begingroup$
    @user673679 yes I did, and didn't want to use it;
    $endgroup$
    – Rick
    12 hours ago

















4












$begingroup$


Intersection of two sorted vectors in C++ - can this be written any better?



vector<int> intersection(vector<int>& nums1, vector<int>& nums2) 
vector<int> result;
int l = 0, r = 0;
while(l < nums1.size() && r < nums2.size())
int left = nums1[l], right = nums2[r];
if(left == right)
result.push_back(right);
while(l < nums1.size() && nums1[l] == left )l++;
while(r < nums2.size() && nums2[r] == right )r++;
continue;

if(left < right)
while(l < nums1.size() && nums1[l] == left )l++;
else while( r < nums2.size() && nums2[r] == right )r++;

return result;










share|improve this question











$endgroup$







  • 4




    $begingroup$
    Do you know about std::set_intersection()? Reference and example implementations: en.cppreference.com/w/cpp/algorithm/set_intersection
    $endgroup$
    – user673679
    12 hours ago






  • 2




    $begingroup$
    @user673679 yes I did, and didn't want to use it;
    $endgroup$
    – Rick
    12 hours ago













4












4








4





$begingroup$


Intersection of two sorted vectors in C++ - can this be written any better?



vector<int> intersection(vector<int>& nums1, vector<int>& nums2) 
vector<int> result;
int l = 0, r = 0;
while(l < nums1.size() && r < nums2.size())
int left = nums1[l], right = nums2[r];
if(left == right)
result.push_back(right);
while(l < nums1.size() && nums1[l] == left )l++;
while(r < nums2.size() && nums2[r] == right )r++;
continue;

if(left < right)
while(l < nums1.size() && nums1[l] == left )l++;
else while( r < nums2.size() && nums2[r] == right )r++;

return result;










share|improve this question











$endgroup$




Intersection of two sorted vectors in C++ - can this be written any better?



vector<int> intersection(vector<int>& nums1, vector<int>& nums2) 
vector<int> result;
int l = 0, r = 0;
while(l < nums1.size() && r < nums2.size())
int left = nums1[l], right = nums2[r];
if(left == right)
result.push_back(right);
while(l < nums1.size() && nums1[l] == left )l++;
while(r < nums2.size() && nums2[r] == right )r++;
continue;

if(left < right)
while(l < nums1.size() && nums1[l] == left )l++;
else while( r < nums2.size() && nums2[r] == right )r++;

return result;







c++ reinventing-the-wheel






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago









Peter Mortensen

25417




25417










asked 14 hours ago









RickRick

308112




308112







  • 4




    $begingroup$
    Do you know about std::set_intersection()? Reference and example implementations: en.cppreference.com/w/cpp/algorithm/set_intersection
    $endgroup$
    – user673679
    12 hours ago






  • 2




    $begingroup$
    @user673679 yes I did, and didn't want to use it;
    $endgroup$
    – Rick
    12 hours ago












  • 4




    $begingroup$
    Do you know about std::set_intersection()? Reference and example implementations: en.cppreference.com/w/cpp/algorithm/set_intersection
    $endgroup$
    – user673679
    12 hours ago






  • 2




    $begingroup$
    @user673679 yes I did, and didn't want to use it;
    $endgroup$
    – Rick
    12 hours ago







4




4




$begingroup$
Do you know about std::set_intersection()? Reference and example implementations: en.cppreference.com/w/cpp/algorithm/set_intersection
$endgroup$
– user673679
12 hours ago




$begingroup$
Do you know about std::set_intersection()? Reference and example implementations: en.cppreference.com/w/cpp/algorithm/set_intersection
$endgroup$
– user673679
12 hours ago




2




2




$begingroup$
@user673679 yes I did, and didn't want to use it;
$endgroup$
– Rick
12 hours ago




$begingroup$
@user673679 yes I did, and didn't want to use it;
$endgroup$
– Rick
12 hours ago










2 Answers
2






active

oldest

votes


















11












$begingroup$


  • Indentation



    Your indentation is not consistent. This makes the code hard to read and maintain. It should be fixed so you don't give other people headaches.



     if(left < right)
    while(l < nums1.size() && nums1[l] == left )l++;
    else while( r < nums2.size() && nums2[r] == right )r++;


    That is basically unreadable giberish (opinion of Martin).




  • Using namespace std; is super bad



    This is mention in nearly every C++ review. There is a large article on the subject here: Why is “using namespace std” considered bad practice?. The second answer is the best in my opinion (Martin) see




  • Multiple declarations in one is bad (thanks to terrible syntax binding rules)



    The one declaration per line has been written about adnausium in best practice guides. Please for the sake of your reader declare one variable per line with its own exact type.



    The syntax binding rules alluded to above is:



    int* x, y; // Here x is int* and y in int
    // confusing to a reader. Did you really mean to make y an int?
    // Avoid this problem be declaring one variable per line



  • Typically, functions like this would be based on iterators to work on any container



    Here your code is limited to only using vectors. But the algorithm you are using could be used by any container type with only small modifications. As a result your function could provide much more utility being written to use iterators.



    The standard library was written such that iterators are the glue between algorithms and container.



  • It would be a lot simpler, if not necessarily more efficient at runtime, to just use some hash sets.


  • This function could be generic in T rather than assuming int.

  • The repeated conditions make me feel like there's simplification waiting here, although exactly what that is eludes me in the two minutes I'm spending on this.

  • Should take by const ref, not ref, so that you can operate on temporaries.





share|improve this answer











$endgroup$








  • 1




    $begingroup$
    You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
    $endgroup$
    – pacmaninbw
    13 hours ago






  • 2




    $begingroup$
    @pacmaninbw: Added some context.
    $endgroup$
    – Martin York
    10 hours ago


















6












$begingroup$

I invite you to review @DeadMG's answer.



Rewriting following (most of) his advice, you'd get something like:



#include <cassert>
#include <algorithm>
#include <vector>

std::vector<T> intersection(std::vector<T> const& left_vector, std::vector<T> const& right_vector)
auto left = left_vector.begin();
auto left_end = left_vector.end();
auto right = right_vector.begin();
auto right_end = right_vector.end();

assert(std::is_sorted(left, left_end));
assert(std::is_sorted(right, right_end));

std::vector<T> result;

while (left != left_end && right != right_end)
if (*left == *right)
result.push_back(*left);
++left;
++right;
continue;


if (*left < *right)
++left;
continue;


assert(*left > *right);
++right;


return result;



I've always found taking pairs of iterators awkward, so I would not recommend such an interface. Instead, you could take simply take any "iterable", they need not even have the same value type, so long as they are comparable:



template <typename Left, typename Right>
std::vector<typename Left::value_type> intersection(Left const& left_c, Right const& right_c);


Also, note that I've included some assert to validate the pre-conditions of the methods (the collections must be sorted) as well as internal invariants (if *left is neither equal nor strictly less than *right then it must be strictly greater).



I encourage you to use assert liberally:



  • They document intentions: pre-conditions, invariants, etc...

  • They check that those intentions hold.

Documentation & Bug detection rolled in one, with no run-time (Release) cost.






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
    $endgroup$
    – Martin York
    10 hours ago






  • 1




    $begingroup$
    @MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
    $endgroup$
    – Matthieu M.
    9 hours ago










  • $begingroup$
    @MatthieuM. You should reconsider the solution you posted.
    $endgroup$
    – Rick
    4 hours ago











Your Answer





StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
);
);
, "mathjax-editing");

StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "196"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216861%2fintersection-of-two-sorted-vectors-in-c%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









11












$begingroup$


  • Indentation



    Your indentation is not consistent. This makes the code hard to read and maintain. It should be fixed so you don't give other people headaches.



     if(left < right)
    while(l < nums1.size() && nums1[l] == left )l++;
    else while( r < nums2.size() && nums2[r] == right )r++;


    That is basically unreadable giberish (opinion of Martin).




  • Using namespace std; is super bad



    This is mention in nearly every C++ review. There is a large article on the subject here: Why is “using namespace std” considered bad practice?. The second answer is the best in my opinion (Martin) see




  • Multiple declarations in one is bad (thanks to terrible syntax binding rules)



    The one declaration per line has been written about adnausium in best practice guides. Please for the sake of your reader declare one variable per line with its own exact type.



    The syntax binding rules alluded to above is:



    int* x, y; // Here x is int* and y in int
    // confusing to a reader. Did you really mean to make y an int?
    // Avoid this problem be declaring one variable per line



  • Typically, functions like this would be based on iterators to work on any container



    Here your code is limited to only using vectors. But the algorithm you are using could be used by any container type with only small modifications. As a result your function could provide much more utility being written to use iterators.



    The standard library was written such that iterators are the glue between algorithms and container.



  • It would be a lot simpler, if not necessarily more efficient at runtime, to just use some hash sets.


  • This function could be generic in T rather than assuming int.

  • The repeated conditions make me feel like there's simplification waiting here, although exactly what that is eludes me in the two minutes I'm spending on this.

  • Should take by const ref, not ref, so that you can operate on temporaries.





share|improve this answer











$endgroup$








  • 1




    $begingroup$
    You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
    $endgroup$
    – pacmaninbw
    13 hours ago






  • 2




    $begingroup$
    @pacmaninbw: Added some context.
    $endgroup$
    – Martin York
    10 hours ago















11












$begingroup$


  • Indentation



    Your indentation is not consistent. This makes the code hard to read and maintain. It should be fixed so you don't give other people headaches.



     if(left < right)
    while(l < nums1.size() && nums1[l] == left )l++;
    else while( r < nums2.size() && nums2[r] == right )r++;


    That is basically unreadable giberish (opinion of Martin).




  • Using namespace std; is super bad



    This is mention in nearly every C++ review. There is a large article on the subject here: Why is “using namespace std” considered bad practice?. The second answer is the best in my opinion (Martin) see




  • Multiple declarations in one is bad (thanks to terrible syntax binding rules)



    The one declaration per line has been written about adnausium in best practice guides. Please for the sake of your reader declare one variable per line with its own exact type.



    The syntax binding rules alluded to above is:



    int* x, y; // Here x is int* and y in int
    // confusing to a reader. Did you really mean to make y an int?
    // Avoid this problem be declaring one variable per line



  • Typically, functions like this would be based on iterators to work on any container



    Here your code is limited to only using vectors. But the algorithm you are using could be used by any container type with only small modifications. As a result your function could provide much more utility being written to use iterators.



    The standard library was written such that iterators are the glue between algorithms and container.



  • It would be a lot simpler, if not necessarily more efficient at runtime, to just use some hash sets.


  • This function could be generic in T rather than assuming int.

  • The repeated conditions make me feel like there's simplification waiting here, although exactly what that is eludes me in the two minutes I'm spending on this.

  • Should take by const ref, not ref, so that you can operate on temporaries.





share|improve this answer











$endgroup$








  • 1




    $begingroup$
    You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
    $endgroup$
    – pacmaninbw
    13 hours ago






  • 2




    $begingroup$
    @pacmaninbw: Added some context.
    $endgroup$
    – Martin York
    10 hours ago













11












11








11





$begingroup$


  • Indentation



    Your indentation is not consistent. This makes the code hard to read and maintain. It should be fixed so you don't give other people headaches.



     if(left < right)
    while(l < nums1.size() && nums1[l] == left )l++;
    else while( r < nums2.size() && nums2[r] == right )r++;


    That is basically unreadable giberish (opinion of Martin).




  • Using namespace std; is super bad



    This is mention in nearly every C++ review. There is a large article on the subject here: Why is “using namespace std” considered bad practice?. The second answer is the best in my opinion (Martin) see




  • Multiple declarations in one is bad (thanks to terrible syntax binding rules)



    The one declaration per line has been written about adnausium in best practice guides. Please for the sake of your reader declare one variable per line with its own exact type.



    The syntax binding rules alluded to above is:



    int* x, y; // Here x is int* and y in int
    // confusing to a reader. Did you really mean to make y an int?
    // Avoid this problem be declaring one variable per line



  • Typically, functions like this would be based on iterators to work on any container



    Here your code is limited to only using vectors. But the algorithm you are using could be used by any container type with only small modifications. As a result your function could provide much more utility being written to use iterators.



    The standard library was written such that iterators are the glue between algorithms and container.



  • It would be a lot simpler, if not necessarily more efficient at runtime, to just use some hash sets.


  • This function could be generic in T rather than assuming int.

  • The repeated conditions make me feel like there's simplification waiting here, although exactly what that is eludes me in the two minutes I'm spending on this.

  • Should take by const ref, not ref, so that you can operate on temporaries.





share|improve this answer











$endgroup$




  • Indentation



    Your indentation is not consistent. This makes the code hard to read and maintain. It should be fixed so you don't give other people headaches.



     if(left < right)
    while(l < nums1.size() && nums1[l] == left )l++;
    else while( r < nums2.size() && nums2[r] == right )r++;


    That is basically unreadable giberish (opinion of Martin).




  • Using namespace std; is super bad



    This is mention in nearly every C++ review. There is a large article on the subject here: Why is “using namespace std” considered bad practice?. The second answer is the best in my opinion (Martin) see




  • Multiple declarations in one is bad (thanks to terrible syntax binding rules)



    The one declaration per line has been written about adnausium in best practice guides. Please for the sake of your reader declare one variable per line with its own exact type.



    The syntax binding rules alluded to above is:



    int* x, y; // Here x is int* and y in int
    // confusing to a reader. Did you really mean to make y an int?
    // Avoid this problem be declaring one variable per line



  • Typically, functions like this would be based on iterators to work on any container



    Here your code is limited to only using vectors. But the algorithm you are using could be used by any container type with only small modifications. As a result your function could provide much more utility being written to use iterators.



    The standard library was written such that iterators are the glue between algorithms and container.



  • It would be a lot simpler, if not necessarily more efficient at runtime, to just use some hash sets.


  • This function could be generic in T rather than assuming int.

  • The repeated conditions make me feel like there's simplification waiting here, although exactly what that is eludes me in the two minutes I'm spending on this.

  • Should take by const ref, not ref, so that you can operate on temporaries.






share|improve this answer














share|improve this answer



share|improve this answer








edited 33 mins ago









Peter Mortensen

25417




25417










answered 14 hours ago









DeadMGDeadMG

759612




759612







  • 1




    $begingroup$
    You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
    $endgroup$
    – pacmaninbw
    13 hours ago






  • 2




    $begingroup$
    @pacmaninbw: Added some context.
    $endgroup$
    – Martin York
    10 hours ago












  • 1




    $begingroup$
    You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
    $endgroup$
    – pacmaninbw
    13 hours ago






  • 2




    $begingroup$
    @pacmaninbw: Added some context.
    $endgroup$
    – Martin York
    10 hours ago







1




1




$begingroup$
You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
$endgroup$
– pacmaninbw
13 hours ago




$begingroup$
You caught the problems and I voted you up, but you could improve your answer by explaining what the issue for the first 4 bullet items.
$endgroup$
– pacmaninbw
13 hours ago




2




2




$begingroup$
@pacmaninbw: Added some context.
$endgroup$
– Martin York
10 hours ago




$begingroup$
@pacmaninbw: Added some context.
$endgroup$
– Martin York
10 hours ago













6












$begingroup$

I invite you to review @DeadMG's answer.



Rewriting following (most of) his advice, you'd get something like:



#include <cassert>
#include <algorithm>
#include <vector>

std::vector<T> intersection(std::vector<T> const& left_vector, std::vector<T> const& right_vector)
auto left = left_vector.begin();
auto left_end = left_vector.end();
auto right = right_vector.begin();
auto right_end = right_vector.end();

assert(std::is_sorted(left, left_end));
assert(std::is_sorted(right, right_end));

std::vector<T> result;

while (left != left_end && right != right_end)
if (*left == *right)
result.push_back(*left);
++left;
++right;
continue;


if (*left < *right)
++left;
continue;


assert(*left > *right);
++right;


return result;



I've always found taking pairs of iterators awkward, so I would not recommend such an interface. Instead, you could take simply take any "iterable", they need not even have the same value type, so long as they are comparable:



template <typename Left, typename Right>
std::vector<typename Left::value_type> intersection(Left const& left_c, Right const& right_c);


Also, note that I've included some assert to validate the pre-conditions of the methods (the collections must be sorted) as well as internal invariants (if *left is neither equal nor strictly less than *right then it must be strictly greater).



I encourage you to use assert liberally:



  • They document intentions: pre-conditions, invariants, etc...

  • They check that those intentions hold.

Documentation & Bug detection rolled in one, with no run-time (Release) cost.






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
    $endgroup$
    – Martin York
    10 hours ago






  • 1




    $begingroup$
    @MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
    $endgroup$
    – Matthieu M.
    9 hours ago










  • $begingroup$
    @MatthieuM. You should reconsider the solution you posted.
    $endgroup$
    – Rick
    4 hours ago















6












$begingroup$

I invite you to review @DeadMG's answer.



Rewriting following (most of) his advice, you'd get something like:



#include <cassert>
#include <algorithm>
#include <vector>

std::vector<T> intersection(std::vector<T> const& left_vector, std::vector<T> const& right_vector)
auto left = left_vector.begin();
auto left_end = left_vector.end();
auto right = right_vector.begin();
auto right_end = right_vector.end();

assert(std::is_sorted(left, left_end));
assert(std::is_sorted(right, right_end));

std::vector<T> result;

while (left != left_end && right != right_end)
if (*left == *right)
result.push_back(*left);
++left;
++right;
continue;


if (*left < *right)
++left;
continue;


assert(*left > *right);
++right;


return result;



I've always found taking pairs of iterators awkward, so I would not recommend such an interface. Instead, you could take simply take any "iterable", they need not even have the same value type, so long as they are comparable:



template <typename Left, typename Right>
std::vector<typename Left::value_type> intersection(Left const& left_c, Right const& right_c);


Also, note that I've included some assert to validate the pre-conditions of the methods (the collections must be sorted) as well as internal invariants (if *left is neither equal nor strictly less than *right then it must be strictly greater).



I encourage you to use assert liberally:



  • They document intentions: pre-conditions, invariants, etc...

  • They check that those intentions hold.

Documentation & Bug detection rolled in one, with no run-time (Release) cost.






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
    $endgroup$
    – Martin York
    10 hours ago






  • 1




    $begingroup$
    @MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
    $endgroup$
    – Matthieu M.
    9 hours ago










  • $begingroup$
    @MatthieuM. You should reconsider the solution you posted.
    $endgroup$
    – Rick
    4 hours ago













6












6








6





$begingroup$

I invite you to review @DeadMG's answer.



Rewriting following (most of) his advice, you'd get something like:



#include <cassert>
#include <algorithm>
#include <vector>

std::vector<T> intersection(std::vector<T> const& left_vector, std::vector<T> const& right_vector)
auto left = left_vector.begin();
auto left_end = left_vector.end();
auto right = right_vector.begin();
auto right_end = right_vector.end();

assert(std::is_sorted(left, left_end));
assert(std::is_sorted(right, right_end));

std::vector<T> result;

while (left != left_end && right != right_end)
if (*left == *right)
result.push_back(*left);
++left;
++right;
continue;


if (*left < *right)
++left;
continue;


assert(*left > *right);
++right;


return result;



I've always found taking pairs of iterators awkward, so I would not recommend such an interface. Instead, you could take simply take any "iterable", they need not even have the same value type, so long as they are comparable:



template <typename Left, typename Right>
std::vector<typename Left::value_type> intersection(Left const& left_c, Right const& right_c);


Also, note that I've included some assert to validate the pre-conditions of the methods (the collections must be sorted) as well as internal invariants (if *left is neither equal nor strictly less than *right then it must be strictly greater).



I encourage you to use assert liberally:



  • They document intentions: pre-conditions, invariants, etc...

  • They check that those intentions hold.

Documentation & Bug detection rolled in one, with no run-time (Release) cost.






share|improve this answer









$endgroup$



I invite you to review @DeadMG's answer.



Rewriting following (most of) his advice, you'd get something like:



#include <cassert>
#include <algorithm>
#include <vector>

std::vector<T> intersection(std::vector<T> const& left_vector, std::vector<T> const& right_vector)
auto left = left_vector.begin();
auto left_end = left_vector.end();
auto right = right_vector.begin();
auto right_end = right_vector.end();

assert(std::is_sorted(left, left_end));
assert(std::is_sorted(right, right_end));

std::vector<T> result;

while (left != left_end && right != right_end)
if (*left == *right)
result.push_back(*left);
++left;
++right;
continue;


if (*left < *right)
++left;
continue;


assert(*left > *right);
++right;


return result;



I've always found taking pairs of iterators awkward, so I would not recommend such an interface. Instead, you could take simply take any "iterable", they need not even have the same value type, so long as they are comparable:



template <typename Left, typename Right>
std::vector<typename Left::value_type> intersection(Left const& left_c, Right const& right_c);


Also, note that I've included some assert to validate the pre-conditions of the methods (the collections must be sorted) as well as internal invariants (if *left is neither equal nor strictly less than *right then it must be strictly greater).



I encourage you to use assert liberally:



  • They document intentions: pre-conditions, invariants, etc...

  • They check that those intentions hold.

Documentation & Bug detection rolled in one, with no run-time (Release) cost.







share|improve this answer












share|improve this answer



share|improve this answer










answered 10 hours ago









Matthieu M.Matthieu M.

2,1871810




2,1871810







  • 1




    $begingroup$
    Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
    $endgroup$
    – Martin York
    10 hours ago






  • 1




    $begingroup$
    @MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
    $endgroup$
    – Matthieu M.
    9 hours ago










  • $begingroup$
    @MatthieuM. You should reconsider the solution you posted.
    $endgroup$
    – Rick
    4 hours ago












  • 1




    $begingroup$
    Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
    $endgroup$
    – Martin York
    10 hours ago






  • 1




    $begingroup$
    @MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
    $endgroup$
    – Matthieu M.
    9 hours ago










  • $begingroup$
    @MatthieuM. You should reconsider the solution you posted.
    $endgroup$
    – Rick
    4 hours ago







1




1




$begingroup$
Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
$endgroup$
– Martin York
10 hours ago




$begingroup$
Why don't you post that as its own questions. There are some improvements even if we don't move to iterators like using template template types.
$endgroup$
– Martin York
10 hours ago




1




1




$begingroup$
@MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
$endgroup$
– Matthieu M.
9 hours ago




$begingroup$
@MartinYork: I generally don't find "template template" to be an improvement, they're quite awkward to use, and tend to constrain the inputs more than intended.
$endgroup$
– Matthieu M.
9 hours ago












$begingroup$
@MatthieuM. You should reconsider the solution you posted.
$endgroup$
– Rick
4 hours ago




$begingroup$
@MatthieuM. You should reconsider the solution you posted.
$endgroup$
– Rick
4 hours ago

















draft saved

draft discarded
















































Thanks for contributing an answer to Code Review Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216861%2fintersection-of-two-sorted-vectors-in-c%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Reverse int within the 32-bit signed integer range: [−2^31, 2^31 − 1]Combining two 32-bit integers into one 64-bit integerDetermine if an int is within rangeLossy packing 32 bit integer to 16 bitComputing the square root of a 64-bit integerKeeping integer addition within boundsSafe multiplication of two 64-bit signed integersLeetcode 10: Regular Expression MatchingSigned integer-to-ascii x86_64 assembler macroReverse the digits of an Integer“Add two numbers given in reverse order from a linked list”

Category:Fedor von Bock Media in category "Fedor von Bock"Navigation menuUpload mediaISNI: 0000 0000 5511 3417VIAF ID: 24712551GND ID: 119294796Library of Congress authority ID: n96068363BnF ID: 12534305fSUDOC authorities ID: 034604189Open Library ID: OL338253ANKCR AUT ID: jn19990000869National Library of Israel ID: 000514068National Thesaurus for Author Names ID: 341574317ReasonatorScholiaStatistics

Kiel Indholdsfortegnelse Historie | Transport og færgeforbindelser | Sejlsport og anden sport | Kultur | Kendte personer fra Kiel | Noter | Litteratur | Eksterne henvisninger | Navigationsmenuwww.kiel.de54°19′31″N 10°8′26″Ø / 54.32528°N 10.14056°Ø / 54.32528; 10.14056Oberbürgermeister Dr. Ulf Kämpferwww.statistik-nord.deDen danske Stats StatistikKiels hjemmesiderrrWorldCat312794080n790547494030481-4