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Delete all lines which don't have n characters before delimiter
The 2019 Stack Overflow Developer Survey Results Are InHow can I wrap text at a certain column size?Delete all lines containing “..” and “@”How can I do a binary search of a text file for a specific character string?Count all lines between a delimiterDelete all lines of text that isn't all numbersHow to print the inputted pattern which don't have matching lines?If Extra delimiter delete last delimiterDelete last characters before delimiterHow to delete all lines that contain only duplicates characters?Delete n lines after pattern and m lines before pattern
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
5080 Cisco Systems, Inc
0E+00 ASUSTek COMPUTER INC.
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
2354 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep
/sed
/awk
/perl
to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?
P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000
-> FFFFFF
)? Should I just use sort
?
text-processing sed grep text-formatting
add a comment |
I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
5080 Cisco Systems, Inc
0E+00 ASUSTek COMPUTER INC.
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
2354 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep
/sed
/awk
/perl
to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?
P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000
-> FFFFFF
)? Should I just use sort
?
text-processing sed grep text-formatting
add a comment |
I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
5080 Cisco Systems, Inc
0E+00 ASUSTek COMPUTER INC.
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
2354 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep
/sed
/awk
/perl
to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?
P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000
-> FFFFFF
)? Should I just use sort
?
text-processing sed grep text-formatting
I have a very long text file (from here) which should contain 6 hexadecimal characters then a 'break' (which appears as one character and doesn't seem to show up properly in the code markdown below) followed by a few words:
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
5080 Cisco Systems, Inc
0E+00 ASUSTek COMPUTER INC.
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
2354 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
I've done some looking around and can't see something which would work in this situation. My question is, how can I use grep
/sed
/awk
/perl
to delete all lines of this text file which do not start with exactly 6 hexadecimal characters and then a 'break'?
P.S. For bonus points, what's the best way of sorting the file alphabetically and numerically according to the hex characters (i.e. 000000
-> FFFFFF
)? Should I just use sort
?
text-processing sed grep text-formatting
text-processing sed grep text-formatting
edited 11 hours ago
codeforester
405418
405418
asked 13 hours ago
RoccoRocco
684
684
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$ awk '$1 ~ /^[[:xdigit:]]6$/' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
This uses awk
to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]]
pattern matches a hexadecimal digit, and 6
requires six of them. Together with the anchoring to the start and end of the field with ^
and $
respectively, this will only match on the wanted lines.
Redirect to some file to save it under a new name.
Note that this seems to work with GNU awk
(commonly found on Linux), but not with awk
on e.g. OpenBSD, or mawk
.
A similar approach with sed
:
$ sed -n '/^[[:xdigit:]]6>/p' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
In this expression, >
is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The >
pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.
For sorting the resulting data, just pipe the result trough sort
, or sort -f
if your hexadecimal numbers uses both upper and lower case letters
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
add a comment |
And for completeness, you can do this with grep too:
$ grep -E '^[[:xdigit:]]6b' oui.txt
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
$
This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b
).
add a comment |
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2 Answers
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active
oldest
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$ awk '$1 ~ /^[[:xdigit:]]6$/' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
This uses awk
to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]]
pattern matches a hexadecimal digit, and 6
requires six of them. Together with the anchoring to the start and end of the field with ^
and $
respectively, this will only match on the wanted lines.
Redirect to some file to save it under a new name.
Note that this seems to work with GNU awk
(commonly found on Linux), but not with awk
on e.g. OpenBSD, or mawk
.
A similar approach with sed
:
$ sed -n '/^[[:xdigit:]]6>/p' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
In this expression, >
is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The >
pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.
For sorting the resulting data, just pipe the result trough sort
, or sort -f
if your hexadecimal numbers uses both upper and lower case letters
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
add a comment |
$ awk '$1 ~ /^[[:xdigit:]]6$/' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
This uses awk
to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]]
pattern matches a hexadecimal digit, and 6
requires six of them. Together with the anchoring to the start and end of the field with ^
and $
respectively, this will only match on the wanted lines.
Redirect to some file to save it under a new name.
Note that this seems to work with GNU awk
(commonly found on Linux), but not with awk
on e.g. OpenBSD, or mawk
.
A similar approach with sed
:
$ sed -n '/^[[:xdigit:]]6>/p' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
In this expression, >
is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The >
pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.
For sorting the resulting data, just pipe the result trough sort
, or sort -f
if your hexadecimal numbers uses both upper and lower case letters
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
add a comment |
$ awk '$1 ~ /^[[:xdigit:]]6$/' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
This uses awk
to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]]
pattern matches a hexadecimal digit, and 6
requires six of them. Together with the anchoring to the start and end of the field with ^
and $
respectively, this will only match on the wanted lines.
Redirect to some file to save it under a new name.
Note that this seems to work with GNU awk
(commonly found on Linux), but not with awk
on e.g. OpenBSD, or mawk
.
A similar approach with sed
:
$ sed -n '/^[[:xdigit:]]6>/p' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
In this expression, >
is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The >
pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.
For sorting the resulting data, just pipe the result trough sort
, or sort -f
if your hexadecimal numbers uses both upper and lower case letters
$ awk '$1 ~ /^[[:xdigit:]]6$/' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
This uses awk
to extract the lines that contains exactly six hexadecimal digits in the first field. The [[:xdigit:]]
pattern matches a hexadecimal digit, and 6
requires six of them. Together with the anchoring to the start and end of the field with ^
and $
respectively, this will only match on the wanted lines.
Redirect to some file to save it under a new name.
Note that this seems to work with GNU awk
(commonly found on Linux), but not with awk
on e.g. OpenBSD, or mawk
.
A similar approach with sed
:
$ sed -n '/^[[:xdigit:]]6>/p' file
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
In this expression, >
is used to match the end of the hexadecimal number. This ensures that longer numbers are not matched. The >
pattern matches a word boundary, i.e. the zero-width space between a word character and a non-word character.
For sorting the resulting data, just pipe the result trough sort
, or sort -f
if your hexadecimal numbers uses both upper and lower case letters
edited 12 hours ago
answered 13 hours ago
Kusalananda♦Kusalananda
141k17262438
141k17262438
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
add a comment |
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
Perfect, thank you very much. Exactly what I was looking for!
– Rocco
12 hours ago
add a comment |
And for completeness, you can do this with grep too:
$ grep -E '^[[:xdigit:]]6b' oui.txt
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
$
This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b
).
add a comment |
And for completeness, you can do this with grep too:
$ grep -E '^[[:xdigit:]]6b' oui.txt
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
$
This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b
).
add a comment |
And for completeness, you can do this with grep too:
$ grep -E '^[[:xdigit:]]6b' oui.txt
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
$
This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b
).
And for completeness, you can do this with grep too:
$ grep -E '^[[:xdigit:]]6b' oui.txt
00107B Cisco Systems, Inc
00906D Cisco Systems, Inc
0090BF Cisco Systems, Inc
000C6E ASUSTek COMPUTER INC.
001BFC ASUSTek COMPUTER INC.
001E8C ASUSTek COMPUTER INC.
0015F2 ASUSTek COMPUTER INC.
001FC6 ASUSTek COMPUTER INC.
60182E ShenZhen Protruly Electronic Ltd co.
F4CFE2 Cisco Systems, Inc
501CBF Cisco Systems, Inc
$
This extended grep expression searches for exactly 6 hex digits at the beginning of each line, followed immediately by a non-whitespace-to-whitespace boundary (b
).
answered 7 hours ago
Digital TraumaDigital Trauma
6,09211730
6,09211730
add a comment |
add a comment |
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