Can this equation be simplified further? The Next CEO of Stack OverflowHow can this trig equation be simplified?Can this be simplified?How can this equation be simplified this way? Transmission line: ZinTaking the integral of a strange function.Evaluating Complex ExpressionsHow should trigonometric expressions be simplified?How can we show $cos^6x+sin^6x=1-3sin^2x cos^2x$?Roots of complex quadratic polynomialCan $Asin^2t + Bsin tcos t + Csin t + Dcos t + E = 0$ be solved algebraically?How was this equation simplified?
How to prove a simple equation?
Grabbing quick drinks
Make solar eclipses exceedingly rare, but still have new moons
How did people program for Consoles with multiple CPUs?
Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?
TikZ: How to reverse arrow direction without switching start/end point?
Why don't programming languages automatically manage the synchronous/asynchronous problem?
Calculator final project in Python
Chain wire methods together in Lightning Web Components
Why didn't Khan get resurrected in the Genesis Explosion?
Does Germany produce more waste than the US?
Where do students learn to solve polynomial equations these days?
What connection does MS Office have to Netscape Navigator?
Flying from Cape Town to England and return to another province
Why doesn't UK go for the same deal Japan has with EU to resolve Brexit?
Is it ever safe to open a suspicious HTML file (e.g. email attachment)?
Won the lottery - how do I keep the money?
Help understanding this unsettling image of Titan, Epimetheus, and Saturn's rings?
Example of a Mathematician/Physicist whose Other Publications during their PhD eclipsed their PhD Thesis
Domestic-to-international connection at Orlando (MCO)
How many extra stops do monopods offer for tele photographs?
WOW air has ceased operation, can I get my tickets refunded?
Is wanting to ask what to write an indication that you need to change your story?
What happened in Rome, when the western empire "fell"?
Can this equation be simplified further?
The Next CEO of Stack OverflowHow can this trig equation be simplified?Can this be simplified?How can this equation be simplified this way? Transmission line: ZinTaking the integral of a strange function.Evaluating Complex ExpressionsHow should trigonometric expressions be simplified?How can we show $cos^6x+sin^6x=1-3sin^2x cos^2x$?Roots of complex quadratic polynomialCan $Asin^2t + Bsin tcos t + Csin t + Dcos t + E = 0$ be solved algebraically?How was this equation simplified?
$begingroup$
I'm trying to simplify the following equation:
$y = dfrac1-2exp(-x)cos(x)+exp(-2x)1+2exp(-x)sin(x)-exp(-2x)$
I suspect that a simpler form using complex exponents exists, but I can't find it.
For context, this equation describes the effective conductivity due to the skin effect of a flat conductor as a function of its thickness. I just removed some scale factors for simplicity. The underlying differential equation gives rise to expressions of the form $exp(pm(1+i)x)$, which is where the $sin(x)$ and $cos(x)$ came from.
trigonometry complex-numbers
New contributor
$endgroup$
add a comment |
$begingroup$
I'm trying to simplify the following equation:
$y = dfrac1-2exp(-x)cos(x)+exp(-2x)1+2exp(-x)sin(x)-exp(-2x)$
I suspect that a simpler form using complex exponents exists, but I can't find it.
For context, this equation describes the effective conductivity due to the skin effect of a flat conductor as a function of its thickness. I just removed some scale factors for simplicity. The underlying differential equation gives rise to expressions of the form $exp(pm(1+i)x)$, which is where the $sin(x)$ and $cos(x)$ came from.
trigonometry complex-numbers
New contributor
$endgroup$
add a comment |
$begingroup$
I'm trying to simplify the following equation:
$y = dfrac1-2exp(-x)cos(x)+exp(-2x)1+2exp(-x)sin(x)-exp(-2x)$
I suspect that a simpler form using complex exponents exists, but I can't find it.
For context, this equation describes the effective conductivity due to the skin effect of a flat conductor as a function of its thickness. I just removed some scale factors for simplicity. The underlying differential equation gives rise to expressions of the form $exp(pm(1+i)x)$, which is where the $sin(x)$ and $cos(x)$ came from.
trigonometry complex-numbers
New contributor
$endgroup$
I'm trying to simplify the following equation:
$y = dfrac1-2exp(-x)cos(x)+exp(-2x)1+2exp(-x)sin(x)-exp(-2x)$
I suspect that a simpler form using complex exponents exists, but I can't find it.
For context, this equation describes the effective conductivity due to the skin effect of a flat conductor as a function of its thickness. I just removed some scale factors for simplicity. The underlying differential equation gives rise to expressions of the form $exp(pm(1+i)x)$, which is where the $sin(x)$ and $cos(x)$ came from.
trigonometry complex-numbers
trigonometry complex-numbers
New contributor
New contributor
New contributor
asked 1 hour ago
Maarten BaertMaarten Baert
82
82
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
$$y=frac1-2e^-xcos(x)+e^-2x1+2e^-xsin(x)-e^-2xcdotfrace^xe^x=frace^x-2cos(x)+e^-xe^x+2sin(x)-e^-xcdotfracfrac12frac12$$ $$=fracfrace^x+e^-x2-cos(x)frace^x-e^-x2+sin(x)=fraccosh(x)-cos(x)sinh(x)+sin(x)$$
$endgroup$
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
1
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
add a comment |
$begingroup$
After coreyman317's answer and your comment about large values of $x$, you could notice that for $x >24$
$$fraccosh(x)-cos(x)sinh(x)+sin(x) sim coth(x)$$ for an error $ < 10^-10$
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Maarten Baert is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3168988%2fcan-this-equation-be-simplified-further%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$$y=frac1-2e^-xcos(x)+e^-2x1+2e^-xsin(x)-e^-2xcdotfrace^xe^x=frace^x-2cos(x)+e^-xe^x+2sin(x)-e^-xcdotfracfrac12frac12$$ $$=fracfrace^x+e^-x2-cos(x)frace^x-e^-x2+sin(x)=fraccosh(x)-cos(x)sinh(x)+sin(x)$$
$endgroup$
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
1
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
add a comment |
$begingroup$
$$y=frac1-2e^-xcos(x)+e^-2x1+2e^-xsin(x)-e^-2xcdotfrace^xe^x=frace^x-2cos(x)+e^-xe^x+2sin(x)-e^-xcdotfracfrac12frac12$$ $$=fracfrace^x+e^-x2-cos(x)frace^x-e^-x2+sin(x)=fraccosh(x)-cos(x)sinh(x)+sin(x)$$
$endgroup$
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
1
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
add a comment |
$begingroup$
$$y=frac1-2e^-xcos(x)+e^-2x1+2e^-xsin(x)-e^-2xcdotfrace^xe^x=frace^x-2cos(x)+e^-xe^x+2sin(x)-e^-xcdotfracfrac12frac12$$ $$=fracfrace^x+e^-x2-cos(x)frace^x-e^-x2+sin(x)=fraccosh(x)-cos(x)sinh(x)+sin(x)$$
$endgroup$
$$y=frac1-2e^-xcos(x)+e^-2x1+2e^-xsin(x)-e^-2xcdotfrace^xe^x=frace^x-2cos(x)+e^-xe^x+2sin(x)-e^-xcdotfracfrac12frac12$$ $$=fracfrace^x+e^-x2-cos(x)frace^x-e^-x2+sin(x)=fraccosh(x)-cos(x)sinh(x)+sin(x)$$
answered 1 hour ago
coreyman317coreyman317
1,059420
1,059420
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
1
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
add a comment |
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
1
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
$begingroup$
Nice! Would it be possible to rewrite this using $tan$ or $tanh$? Unfortunately $sinh(x)$ and $cosh(x)$ cause numerical issues (overflow) for large values of $x$.
$endgroup$
– Maarten Baert
58 mins ago
1
1
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
$begingroup$
If you want you can divide the top and bottom by $cosh(x)$ to get a $tanh(x)$ but this makes both the numerator and denominator more complicated.
$endgroup$
– coreyman317
54 mins ago
add a comment |
$begingroup$
After coreyman317's answer and your comment about large values of $x$, you could notice that for $x >24$
$$fraccosh(x)-cos(x)sinh(x)+sin(x) sim coth(x)$$ for an error $ < 10^-10$
$endgroup$
add a comment |
$begingroup$
After coreyman317's answer and your comment about large values of $x$, you could notice that for $x >24$
$$fraccosh(x)-cos(x)sinh(x)+sin(x) sim coth(x)$$ for an error $ < 10^-10$
$endgroup$
add a comment |
$begingroup$
After coreyman317's answer and your comment about large values of $x$, you could notice that for $x >24$
$$fraccosh(x)-cos(x)sinh(x)+sin(x) sim coth(x)$$ for an error $ < 10^-10$
$endgroup$
After coreyman317's answer and your comment about large values of $x$, you could notice that for $x >24$
$$fraccosh(x)-cos(x)sinh(x)+sin(x) sim coth(x)$$ for an error $ < 10^-10$
answered 38 mins ago
Claude LeiboviciClaude Leibovici
125k1158135
125k1158135
add a comment |
add a comment |
Maarten Baert is a new contributor. Be nice, and check out our Code of Conduct.
Maarten Baert is a new contributor. Be nice, and check out our Code of Conduct.
Maarten Baert is a new contributor. Be nice, and check out our Code of Conduct.
Maarten Baert is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3168988%2fcan-this-equation-be-simplified-further%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown