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Pristine Bit Checking



What is the logic behind how bash tests for true/false?


What is the difference between : and true?What is the builtin `:` used for in Bash?bash script trap for exit and err and logic for differenceWhat is the rationale behind $array not expanding the whole array in ksh and bash?extract columns from TRUE/FALSE matrix based on proportion of TRUE values within the columnExpression evaluates to false in for loop whereas it's true in ifWhy does `source foo && true` exit the script in bash?for loop logic porting from bash to cshBash: how can I run `sudo -n true` in the background without interfering with `read`?What's the purpose of “true” in bash “if sudo true; then”






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















This:



$ echo $VAR
something


And this:



$ [[ -z "$VAR" ]]
$ echo $?
1


Yet this:



if [[ -z "$TMUX_MAN_PANE" ]]; then
echo 'NEVER PRINTS!'


This screws with my head.



UPDATE



Here's some real code. I can't get this to work.



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
tmux list-panes -t $TMUX_MAN_PANE &> /dev/null
echo $?
echo $TMUX_MAN_PANE
[[ -z "$TMUX_MAN_PANE" ]]
echo $?
if ! [[ -z "$TMUX_MAN_PANE" ]] && [[ $? ]]; then
echo luck
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
echo fuck
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi



UPDATE 2: Success



Finally figured it out. Was having problems getting the status of the first line in the if statement. Had to do some trickery to get the output of the tmux statement in the first line of the if statement. If anyone knows a cleaner way to do this, I'm all ears.



Here's the working code:



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
fucker=$(tmux list-panes -t $TMUX_MAN_PANE 2>&1)
if ! [[ -z "$TMUX_MAN_PANE" ]] && ! [[ $fucker =~ 'find pane' ]]; then
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi


tmux_man_page_close()
if [ $TMUX_MAN_PANE ]; then
tmux kill-pane -t $TMUX_MAN_PANE
fi










share|improve this question



















  • 2





    Your update does not include enough information. Please (a) include the values of TERM, TMUX, and TMUX_MAN_PANE from before the function runs and (b) include the output of the function and then (c) explain how that output differs from what you expect.

    – John1024
    yesterday











  • It's all a mess. In the first line of the if statement, I just want to know if that command is throwing an error. There is no seemingly rational way to do that. I don't want the output from the command, I want to know if it's throwing an error. That's it.

    – StevieD
    yesterday












  • It's showing the command was a success even though it can't find the pane. I see no way to extract the output from that tmux command.

    – StevieD
    yesterday











  • I should just be going this in perl. Fuck this crazy shit.

    – StevieD
    yesterday











  • Jesus, finally figured it out. Posting solution.

    – StevieD
    yesterday


















2















This:



$ echo $VAR
something


And this:



$ [[ -z "$VAR" ]]
$ echo $?
1


Yet this:



if [[ -z "$TMUX_MAN_PANE" ]]; then
echo 'NEVER PRINTS!'


This screws with my head.



UPDATE



Here's some real code. I can't get this to work.



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
tmux list-panes -t $TMUX_MAN_PANE &> /dev/null
echo $?
echo $TMUX_MAN_PANE
[[ -z "$TMUX_MAN_PANE" ]]
echo $?
if ! [[ -z "$TMUX_MAN_PANE" ]] && [[ $? ]]; then
echo luck
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
echo fuck
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi



UPDATE 2: Success



Finally figured it out. Was having problems getting the status of the first line in the if statement. Had to do some trickery to get the output of the tmux statement in the first line of the if statement. If anyone knows a cleaner way to do this, I'm all ears.



Here's the working code:



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
fucker=$(tmux list-panes -t $TMUX_MAN_PANE 2>&1)
if ! [[ -z "$TMUX_MAN_PANE" ]] && ! [[ $fucker =~ 'find pane' ]]; then
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi


tmux_man_page_close()
if [ $TMUX_MAN_PANE ]; then
tmux kill-pane -t $TMUX_MAN_PANE
fi










share|improve this question



















  • 2





    Your update does not include enough information. Please (a) include the values of TERM, TMUX, and TMUX_MAN_PANE from before the function runs and (b) include the output of the function and then (c) explain how that output differs from what you expect.

    – John1024
    yesterday











  • It's all a mess. In the first line of the if statement, I just want to know if that command is throwing an error. There is no seemingly rational way to do that. I don't want the output from the command, I want to know if it's throwing an error. That's it.

    – StevieD
    yesterday












  • It's showing the command was a success even though it can't find the pane. I see no way to extract the output from that tmux command.

    – StevieD
    yesterday











  • I should just be going this in perl. Fuck this crazy shit.

    – StevieD
    yesterday











  • Jesus, finally figured it out. Posting solution.

    – StevieD
    yesterday














2












2








2








This:



$ echo $VAR
something


And this:



$ [[ -z "$VAR" ]]
$ echo $?
1


Yet this:



if [[ -z "$TMUX_MAN_PANE" ]]; then
echo 'NEVER PRINTS!'


This screws with my head.



UPDATE



Here's some real code. I can't get this to work.



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
tmux list-panes -t $TMUX_MAN_PANE &> /dev/null
echo $?
echo $TMUX_MAN_PANE
[[ -z "$TMUX_MAN_PANE" ]]
echo $?
if ! [[ -z "$TMUX_MAN_PANE" ]] && [[ $? ]]; then
echo luck
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
echo fuck
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi



UPDATE 2: Success



Finally figured it out. Was having problems getting the status of the first line in the if statement. Had to do some trickery to get the output of the tmux statement in the first line of the if statement. If anyone knows a cleaner way to do this, I'm all ears.



Here's the working code:



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
fucker=$(tmux list-panes -t $TMUX_MAN_PANE 2>&1)
if ! [[ -z "$TMUX_MAN_PANE" ]] && ! [[ $fucker =~ 'find pane' ]]; then
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi


tmux_man_page_close()
if [ $TMUX_MAN_PANE ]; then
tmux kill-pane -t $TMUX_MAN_PANE
fi










share|improve this question
















This:



$ echo $VAR
something


And this:



$ [[ -z "$VAR" ]]
$ echo $?
1


Yet this:



if [[ -z "$TMUX_MAN_PANE" ]]; then
echo 'NEVER PRINTS!'


This screws with my head.



UPDATE



Here's some real code. I can't get this to work.



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
tmux list-panes -t $TMUX_MAN_PANE &> /dev/null
echo $?
echo $TMUX_MAN_PANE
[[ -z "$TMUX_MAN_PANE" ]]
echo $?
if ! [[ -z "$TMUX_MAN_PANE" ]] && [[ $? ]]; then
echo luck
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
echo fuck
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi



UPDATE 2: Success



Finally figured it out. Was having problems getting the status of the first line in the if statement. Had to do some trickery to get the output of the tmux statement in the first line of the if statement. If anyone knows a cleaner way to do this, I'm all ears.



Here's the working code:



tmux_man_page() 
if [[ "$TERM" =~ 'screen' ]] && [[ -n "$TMUX" ]]; then
fucker=$(tmux list-panes -t $TMUX_MAN_PANE 2>&1)
if ! [[ -z "$TMUX_MAN_PANE" ]] && ! [[ $fucker =~ 'find pane' ]]; then
tmux -q respawn-pane -k -t $TMUX_MAN_PANE man $1
else
tmux split-window -vf man $1
TMUX_MAN_PANE=$(tmux display-message -p "#pane_id")
export TMUX_MAN_PANE
tmux select-pane -t last
fi
fi


tmux_man_page_close()
if [ $TMUX_MAN_PANE ]; then
tmux kill-pane -t $TMUX_MAN_PANE
fi







bash






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday









Rui F Ribeiro

42k1483142




42k1483142










asked yesterday









StevieDStevieD

1759




1759







  • 2





    Your update does not include enough information. Please (a) include the values of TERM, TMUX, and TMUX_MAN_PANE from before the function runs and (b) include the output of the function and then (c) explain how that output differs from what you expect.

    – John1024
    yesterday











  • It's all a mess. In the first line of the if statement, I just want to know if that command is throwing an error. There is no seemingly rational way to do that. I don't want the output from the command, I want to know if it's throwing an error. That's it.

    – StevieD
    yesterday












  • It's showing the command was a success even though it can't find the pane. I see no way to extract the output from that tmux command.

    – StevieD
    yesterday











  • I should just be going this in perl. Fuck this crazy shit.

    – StevieD
    yesterday











  • Jesus, finally figured it out. Posting solution.

    – StevieD
    yesterday













  • 2





    Your update does not include enough information. Please (a) include the values of TERM, TMUX, and TMUX_MAN_PANE from before the function runs and (b) include the output of the function and then (c) explain how that output differs from what you expect.

    – John1024
    yesterday











  • It's all a mess. In the first line of the if statement, I just want to know if that command is throwing an error. There is no seemingly rational way to do that. I don't want the output from the command, I want to know if it's throwing an error. That's it.

    – StevieD
    yesterday












  • It's showing the command was a success even though it can't find the pane. I see no way to extract the output from that tmux command.

    – StevieD
    yesterday











  • I should just be going this in perl. Fuck this crazy shit.

    – StevieD
    yesterday











  • Jesus, finally figured it out. Posting solution.

    – StevieD
    yesterday








2




2





Your update does not include enough information. Please (a) include the values of TERM, TMUX, and TMUX_MAN_PANE from before the function runs and (b) include the output of the function and then (c) explain how that output differs from what you expect.

– John1024
yesterday





Your update does not include enough information. Please (a) include the values of TERM, TMUX, and TMUX_MAN_PANE from before the function runs and (b) include the output of the function and then (c) explain how that output differs from what you expect.

– John1024
yesterday













It's all a mess. In the first line of the if statement, I just want to know if that command is throwing an error. There is no seemingly rational way to do that. I don't want the output from the command, I want to know if it's throwing an error. That's it.

– StevieD
yesterday






It's all a mess. In the first line of the if statement, I just want to know if that command is throwing an error. There is no seemingly rational way to do that. I don't want the output from the command, I want to know if it's throwing an error. That's it.

– StevieD
yesterday














It's showing the command was a success even though it can't find the pane. I see no way to extract the output from that tmux command.

– StevieD
yesterday





It's showing the command was a success even though it can't find the pane. I see no way to extract the output from that tmux command.

– StevieD
yesterday













I should just be going this in perl. Fuck this crazy shit.

– StevieD
yesterday





I should just be going this in perl. Fuck this crazy shit.

– StevieD
yesterday













Jesus, finally figured it out. Posting solution.

– StevieD
yesterday






Jesus, finally figured it out. Posting solution.

– StevieD
yesterday











1 Answer
1






active

oldest

votes


















7














The key is that 0 means true and 1 (or any other non-zero value) means false.



In shell, a test that is true (or a program which completes successfully), exits with code 0. The test [[ -z "$VAR" ]] returns code zero (true) if $VAR is empty or one (false) if it is not empty:



$ var=""; [[ -z "$var" ]]; echo $?
0
$ var="NOT EMPTY"; [[ -z "$var" ]]; echo $?
1


In sum, if $VAR is non-empty, then [[ -z "$VAR" ]] is false (returns 1) and the then statement does not execute.



Did you intend for the test to return true if the variable was non-empty? If so, replace -z with -n:



$ var=""; [[ -n "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ -n "$var" ]]; echo $?
0


For brevity, the same test is performed if -n is omitted:



$ var=""; [[ "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ "$var" ]]; echo $?
0





share|improve this answer

























  • I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

    – StevieD
    yesterday






  • 1





    @StevieD Run set -x and then run your code. This will show you how every step is evaluated.

    – John1024
    yesterday












  • Ah, shit. Forgot about that setting. I'll try it.

    – StevieD
    yesterday











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









7














The key is that 0 means true and 1 (or any other non-zero value) means false.



In shell, a test that is true (or a program which completes successfully), exits with code 0. The test [[ -z "$VAR" ]] returns code zero (true) if $VAR is empty or one (false) if it is not empty:



$ var=""; [[ -z "$var" ]]; echo $?
0
$ var="NOT EMPTY"; [[ -z "$var" ]]; echo $?
1


In sum, if $VAR is non-empty, then [[ -z "$VAR" ]] is false (returns 1) and the then statement does not execute.



Did you intend for the test to return true if the variable was non-empty? If so, replace -z with -n:



$ var=""; [[ -n "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ -n "$var" ]]; echo $?
0


For brevity, the same test is performed if -n is omitted:



$ var=""; [[ "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ "$var" ]]; echo $?
0





share|improve this answer

























  • I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

    – StevieD
    yesterday






  • 1





    @StevieD Run set -x and then run your code. This will show you how every step is evaluated.

    – John1024
    yesterday












  • Ah, shit. Forgot about that setting. I'll try it.

    – StevieD
    yesterday















7














The key is that 0 means true and 1 (or any other non-zero value) means false.



In shell, a test that is true (or a program which completes successfully), exits with code 0. The test [[ -z "$VAR" ]] returns code zero (true) if $VAR is empty or one (false) if it is not empty:



$ var=""; [[ -z "$var" ]]; echo $?
0
$ var="NOT EMPTY"; [[ -z "$var" ]]; echo $?
1


In sum, if $VAR is non-empty, then [[ -z "$VAR" ]] is false (returns 1) and the then statement does not execute.



Did you intend for the test to return true if the variable was non-empty? If so, replace -z with -n:



$ var=""; [[ -n "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ -n "$var" ]]; echo $?
0


For brevity, the same test is performed if -n is omitted:



$ var=""; [[ "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ "$var" ]]; echo $?
0





share|improve this answer

























  • I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

    – StevieD
    yesterday






  • 1





    @StevieD Run set -x and then run your code. This will show you how every step is evaluated.

    – John1024
    yesterday












  • Ah, shit. Forgot about that setting. I'll try it.

    – StevieD
    yesterday













7












7








7







The key is that 0 means true and 1 (or any other non-zero value) means false.



In shell, a test that is true (or a program which completes successfully), exits with code 0. The test [[ -z "$VAR" ]] returns code zero (true) if $VAR is empty or one (false) if it is not empty:



$ var=""; [[ -z "$var" ]]; echo $?
0
$ var="NOT EMPTY"; [[ -z "$var" ]]; echo $?
1


In sum, if $VAR is non-empty, then [[ -z "$VAR" ]] is false (returns 1) and the then statement does not execute.



Did you intend for the test to return true if the variable was non-empty? If so, replace -z with -n:



$ var=""; [[ -n "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ -n "$var" ]]; echo $?
0


For brevity, the same test is performed if -n is omitted:



$ var=""; [[ "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ "$var" ]]; echo $?
0





share|improve this answer















The key is that 0 means true and 1 (or any other non-zero value) means false.



In shell, a test that is true (or a program which completes successfully), exits with code 0. The test [[ -z "$VAR" ]] returns code zero (true) if $VAR is empty or one (false) if it is not empty:



$ var=""; [[ -z "$var" ]]; echo $?
0
$ var="NOT EMPTY"; [[ -z "$var" ]]; echo $?
1


In sum, if $VAR is non-empty, then [[ -z "$VAR" ]] is false (returns 1) and the then statement does not execute.



Did you intend for the test to return true if the variable was non-empty? If so, replace -z with -n:



$ var=""; [[ -n "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ -n "$var" ]]; echo $?
0


For brevity, the same test is performed if -n is omitted:



$ var=""; [[ "$var" ]]; echo $?
1
$ var="NOT EMPTY"; [[ "$var" ]]; echo $?
0






share|improve this answer














share|improve this answer



share|improve this answer








edited yesterday

























answered yesterday









John1024John1024

48.5k5113128




48.5k5113128












  • I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

    – StevieD
    yesterday






  • 1





    @StevieD Run set -x and then run your code. This will show you how every step is evaluated.

    – John1024
    yesterday












  • Ah, shit. Forgot about that setting. I'll try it.

    – StevieD
    yesterday

















  • I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

    – StevieD
    yesterday






  • 1





    @StevieD Run set -x and then run your code. This will show you how every step is evaluated.

    – John1024
    yesterday












  • Ah, shit. Forgot about that setting. I'll try it.

    – StevieD
    yesterday
















I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

– StevieD
yesterday





I just posted my real code. I cannot, for the life of me, get that to work. I'm literally going fucking nuts.

– StevieD
yesterday




1




1





@StevieD Run set -x and then run your code. This will show you how every step is evaluated.

– John1024
yesterday






@StevieD Run set -x and then run your code. This will show you how every step is evaluated.

– John1024
yesterday














Ah, shit. Forgot about that setting. I'll try it.

– StevieD
yesterday





Ah, shit. Forgot about that setting. I'll try it.

– StevieD
yesterday

















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